No. A matrix is nonsingular (i.e. invertible) iff its determinant is nonzero. To prove this we note that to solve the eigenvalue equation ##Avecv = lambdavecv## […]
Find the axis of symmetry using the equation ##x=(-b)/(2a)##. Find the vertex by substituting the value for ##x## into the equation and solving for ##y##. There […]