1. The standard deviation of the diameter at breast height or DBH of the slash pine tree is less than one inch. Identify the Type I error. (Points : 1)
Fail to support the claim < 1 when < 1 is true. Support the claim < 1 when = 1 is true. Support the claim < 1 when = 1 is true. Fail to support the claim < 1 when < 1 is true. 1a. The EPA claims that fluoride in children's drinking water should be at a mean level of less than 1.2 ppm or parts per million to reduce the number of dental cavities. Identify the Type I error. (Points : 1) Fail to support the claim < 1.2 when < 1.2 is true.Support the claim < 1.2 when = 1.2 is true.Support the claim < 1.2 when = 1.2 is true.Fail to support the claim < 1.2 when < 1.2 is true. 2. Biologists are investigating if their efforts to prevent erosion on the bank of a stream have been statistically significant. For this stream a narrow channel width is a good indicator that erosion is not occurring. Test the claim that the mean width of ten locations within the stream is greater than 3.7 meters. Assume that a simple random sample has been taken the population standard deviation is not known and the population is normally distributed. Use the following sample data:3.3 3.3 3.5 4.9 3.5 4.1 4.1 5 7.3 6.2What is the P-value associated with your test statistic? Report your answer with three decimals e.g. .987 (Points : 1) 2a. Medical researchers studying two therapies for treating patients infected with Hepatitis C found the following data. Assume a .05 significance level for testing the claim that the proportions are not equal. Also assume the two simple random samples are independent and that the conditions np 5 and nq 5 are satisfied. Therapy 1 Therapy 2 Number of patients 39 47 Eliminated Hepatitis 20 13 C infection Construct a 95% confidence interval estimate of the odds ratio of the odds for having Hepatitis C after Therapy 1 to the odds for having Hepatitis C after Therapy 2. Give your answer with two decimals e.g. (12.3456.78)(Points : 0.5) 3. Researchers studying sleep loss followed the length of sleep in hours of 10 individuals with insomnia before and after cognitive behavioral therapy (CBT). Assume a .05 significance level to test the claim that there is a difference between the length of sleep of individuals before and after CBT. Also assume the data consist of matched pairs the samples are simple random samples and the pairs of values are from a population having a distribution that is approximately normal. Individual 1 2 3 4 5 6 7 8 9 10 Before 6 5 4 5 3 4 5 3 4 2 CBT After 8 8 7 6 7 6 6 5 7 5 CBT Construct a 95% confidence interval estimate of the mean difference between the lengths of sleep. Give your answer with two decimals e.g. (12.3456.78)(Points : 0.5) 3a. Scientists researching large woody debris (LWD) surveyed the number of LWD pieces from aerial photos taken annually for the past 35 years at two different sites. Over the 35 years of photos examined the first site had a mean number of LWD pieces per hectare per year (LWD/ha/yr) of 3.7 pieces with a standard deviation of 1.9. The second site had a mean number of LWD/ha/yr of 4.3 with a standard deviation of 2.4. Assume a .05 significance level for testing the claim that the mean LWD/ha at the first site had less than the mean LWD/ha/yr at the second site. Also assume the two samples are independent simple random samples selected from normally distributed populations but do not assume that the population standard deviations are equal.Construct a 90% confidence interval for the difference between the two means. Give your answer with two decimals e.g. (12.3456.78) (Points : 0.5) 4. The paired data consist of the cost of regionally advertising (in thousands of dollars) a certain pharmaceutical drug and the number of new prescriptions written (in thousands). Cost 9 2 3 4 2 5 9 10 Number 85 52 55 68 67 86 83 73 Find the value of the linear correlation coefficient r. Give your answer to three decimals e.g. .987. (Points : 0.5) 4a. The paired data consist of the cost of regionally advertising (in thousands of dollars) a certain pharmaceutical drug and the number of new prescriptions written (in thousands). Cost 9 2 3 4 2 5 9 10 Number 85 52 55 68 67 86 83 73 Find the predicted value of the number of new prescriptions written if $6000 is spent in regional advertising. Give your answer as an integer.(Points : 0.5) 5. Use a .05 significance level and the observed frequencies of 70 Neonatal deaths to test the claim that number of neonatal deaths on each day of the week is equally likely. Mon Tues Wed Thurs Fri Sat Sun 10 9 5 8 15 12 11 Determine the value of the 2 test statistic. Give your answer to two decimals e.g. 12.34 (Points : 0.5) 5a. Use a .05 significance level and the observed frequencies of 144 drowning at the beaches of a randomly selected coastal state to test the claim that the number of drowning for each month is equally likely. Jan Feb Mar Apr May June July Aug Sept Oct Nov Dec 1 3 2 7 14 20 37 33 16 6 2 3 Determine the value of the 2test statistic. Give your answer to two decimals e.g. 12.34 .(Points : 0.5) 6. Using a .01 significance level test the claim that the proportions of fear/do not fear responses are the same for male and female dental patients.Gender Male Female Fear Dentistry 48 70 Do Not Fear Dentistry 21 32 Do you reject the null hypothesis at the .01 significance level? Enter Y for yes (reject) N for no (fail to reject). (Points : 0.5) 6a. Using a .01 significance level test the claim that the proportions of fear/do not fear responses are the same for male and female dental patients.Gender Male Female Fear Dentistry 48 70 Do Not Fear Dentistry 21 32 Determine the value of the 2test statistic. Give your answer to three decimals e.g. 12.345 .(Points : 0.5) 7. The table represents results from an experiment with patients afflicted in both eyes with glaucoma. Each patient was treated in one eye with laser surgery and in the other eye was treated with eye drops. Using a .05 significance level apply McNemar's test to test the following claim: The proportion of patients with no improvement on the laser treated eye and an improvement on the drops treated eye is the same as the proportion of patients with an improvement on the laser treated eye and no improvement on the drops treated eye. Eye Drop Treatment Improvement No Improvement Laser Surgery Improvement 15 10 Treatment No Improvement 50 25 Determine the value of the 2 test statistic. Give your answer to two decimals e.g. 12.34 . (Points : 0.5) 7a. The table represents results from an experiment with patients afflicted with eczema on both arms. Each patient was treated with an immune modulator cream on one arm and a topical steroid cream on the other arm. Using a .05 significance level apply McNemar's test to test the following claim: The proportion of patients with no cure on the immune modulator treated arm and a cure on the topical steroid treated arm is the same as the proportion of patients with a cure on the immune modulator treated arm and no cure on the topical steroid treated arm. Immune Modulator Cream Cure No Cure Topical Steroid Cure 25 11 Cream No Cure 42 22 Do you reject the null hypothesis at the .05 significance level? Enter Y for yes (reject) N for no (fail to reject).(Points : 0.5) 8.For a study on Type 1 diabetes medical graduate students subdivided the United States into four study regions (Northeast Southeast Southwest and Northwest). The students randomly selected seven patients per region and recorded the number of times during a randomly selected month that each patient used insulin shots to regulate blood sugar levels. Use One-Way ANOVA at a .05 significance level to test the claim that the means from the different regions are not the same. Mean number of times patients used insulin shots to regulate blood sugar levels Northeast Southeast Southwest Northwest 4 6 4 4 3 5 5 4 3 6 6 5 4 8 6 6 3 6 7 3 2 6 5 5 5 8 4 3 Do you reject the null hypothesis at the .05 significance level? Enter Y for yes (reject) N for no (fail to reject). (Points : 0.5 8a. Geneticists studying carriers of genetic diseases followed subjects subdivided by race. Researchers randomly selected seven patients per race who had been identified as carrying a certain gene for a genetic disease; these patients were followed to determine the number of their siblings who also carried the gene for the genetic disease. Use a One-Way ANOVA at a .05 significance level to test the claim that the means from the different races are not all the same. Caucasian African-American Other 2 0 0 3 0 1 3 1 2 3 2 2 4 2 2 5 2 3 5 4 4 Determine the value of the F test statistic. Give your answer to two decimals e.g. 12.34 .(Points : 0.5) 9. The reason we cannot use multiple t-tests to claim that four populations have the same mean is that we increase the likelihood of a type I error. (Points : 1) True False 9a. If there is only one observation per cell in a Two-Way ANOVA and it can be assumed there is not an interaction between factors then we can proceed to interpret the results of the row and column effects. (Points : 1) TrueFalse 10.Use the following technology display from a Two-Way ANOVA to answer this question. Biologists studying habitat use in Lepidopteran moths measured the number of savannah moths found at three randomly selected prairie sites with two potential habitat interferences (expansion of row crops and grazing). Use a .05 significance level. Source Df SS MS F P Site 2 .1905 .0952 .0381 .9627 Habitat 1 304.0238 304.0238 121.6095 .0000 Site*Habitat 2 .1905 .0952 .0381 .9627 What is the value of the F test statistic for the site effect? (Points : 0.5) 10a. Use the following technology display from a Two-Way ANOVA to answer this question. Biologists studying habitat use in Lepidopteran moths measured the number of savannah moths found at three randomly selected prairie sites with two potential habitat interferences (expansion of row crops and grazing). Use a .05 significance level. Source Df SS MS F P Site 2 .1905 .0952 .0381 .9627 Habitat 1 304.0238 304.0238 121.6095 .0000 Site*Habitat 2 .1905 .0952 .0381 .9627 Do you reject the null hypothesis about the site effect at the .05 significance level? Enter Y for yes (reject) N for no (fail to reject).(Points : 0.5)