##AlBr_3 + K_2SO_4 -> KBr + Al_2(SO_4)_3##

How I balance equations is by first of all dividing the equation into two parts – reactants and products.

Reactants Al = 3 Br = 3 K = 2 S = 1 O = 4

Products Al = 2 Br = 1 K = 1 S = 3 O = 12

Remember all atoms within the brackets get multiplied by the number outwith them.

Step 1 Put a 6 before KBr

##AlBr_3 + K_2SO_4 -> 6KBr + Al_2(SO_4)_3##

Step 2 Put a 2 before ##AlBr_3## – this has now balanced the number of Aluminium and Bromine atoms.

##2AlBr_3 + K_2SO_4 -> 6KBr + Al_2(SO_4)_3##

Step 3 Put a 3 before ##K_2SO_4##

This balances the Potassium, Sulphur and Oxyen

##2AlBr_3 + 3K_2SO_4 -> 6KBr + Al_2(SO_4)_3##

Now check the reactants and products:

Reactants Al – 2 Br – 6 K – 6 S – 3 O – 12

Products Al – 2 Br – 6 K – 6 S – 3 O – 12

We have now successfully balanced the equation

I hope this helps!