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2). Find the margin of error for the given values of c, s, and n.
c=0.90 s=3.8 n=81
3.) Find the indicated probability using the standard normal distribution.
P(-2.87<z<2.87)
4.) You are given the sample mean and the sample standard deviation. Use this information to construct 90% and 95% confidence intervals for the population mean. Which interval is wider? A random sample of 39 eight ounce servings of different juice drinks has a mean of 88.5 calories and a standard deviation of 40.4 calories.
The 90% confidence interval is (___,___)
The 95% confidence interval is (___,___)
5.) Find the critical value tc for the confidence level c=0.98 and the sample size is n=6.
6.) The population mean annual salary for environment compliance specialists is about $62,000. A random sample of 38 specialists is drawn from this population. What is the probability that the mean salary of the sample is less than $59500? Assume standard deviation is $5,500.
